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Proof step 20 from proof get-get (previous step)

n→i(n) < j, ∀ j0, n, r, i, st. i→n(j0) < i→n(j) → (n→i(n) < j0 → (getarray(r, i, j0, st)[n]) = st[r -- (i + n→i(n)) ']) ⊦ (getarray(r, i, j, st)[n]) = st[r -- (i + n→i(n)) ']

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ 1 < j → getarray(r, i, j, st) = getarray(r, i, j - 1, st) + st[r -- (i + j - 1) ']
Proof step 3:
¬ 1 < j, n→i(n) < j, ∀ j0, n, r, i, st. i→n(j0) < i→n(j) → (n→i(n) < j0 → (getarray(r, i, j0, st)[n]) = st[r -- (i + n→i(n)) ']) ⊦ (getarray(r, i, j, st)[n]) = st[r -- (i + n→i(n)) ']
Proof step 19:
1 < j, n→i(n) < j, ∀ j0, n, r, i, st. i→n(j0) < i→n(j) → (n→i(n) < j0 → (getarray(r, i, j0, st)[n]) = st[r -- (i + n→i(n)) ']) ⊦ (getarray(r, i, j - 1, st) + st[r -- (i + j - 1) '])[n] = st[r -- (i + n→i(n)) ']

Rule argument

[crewrite-arg: getArray-rec, F, [st, j, i, r] → [st, j, i, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, j, i, r)]]