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Proof step 7 from proof get-puteq (previous step)

getarray(r, i, j, st) = getarray(r0, i, j, st0), 0 ≤ j0, j0 < j, 0 < j ⊦ (((i + j0) ' = sk ⊃ val0; st[r -- (i + j0) '])) = (((i + j0) ' = sk ⊃ val0; st0[r0 -- (i + j0) ']))

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 6:
(i + j0) ' ≠ sk, getarray(r, i, j, st) = getarray(r0, i, j, st0), 0 ≤ j0, j0 < j, 0 < j ⊦ st[r -- (i + j0) '] = (((i + j0) ' = sk ⊃ val0; st0[r0 -- (i + j0) ']))

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + j = j + i])]]