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Proof step 13 from proof get-rec-01 (previous step)

1 < 2 + i2, (~1) ≤ i2, 0 < i2, ∀ i1, r, i, st. i→n(i1) < i→n(i2 + 1) → (0 ≤ i1 → getarray(r, i, i1 + 1, st) = st[r -- i '] ' + getarray(r, i + 1, i1, st)) ⊦ getarray(r, i, 2 + i2 - 1, st) + st[r -- (i + 2 + i2 - 1) '] = st[r -- i '] ' + getarray(r, i + 1, i2, st) + st[r -- (i + i2 + 1) '] '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
0 < i2, 0 ≤ i2, ∀ i1, r, i, st. i→n(i1) < i→n(i2 + 1) → (0 ≤ i1 → getarray(r, i, i1 + 1, st) = st[r -- i '] ' + getarray(r, i + 1, i1, st)) ⊦ getarray(r, i, 1 + i2, st) = st[r -- i '] ' + getarray(r, i + 1, i2, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPSEQ : i0 ≠ 0, i0 ≤ i ⊦ ((* i)) ≤ j → ((* i0)) ≤ j], [CSIMPSEQ : ⊦ (~1) < i ↔ 0 ≤ i], [CSIMPSEQ : ⊦ ((* j)) < i0 + ((* j0)) ↔ j - j0 < i0], [CSIMPSEQ : ⊦ (vals + vals0) + vals1 = vals + vals0 + vals1], [CSIMPSEQ : ⊦ vals + vals0 = vals1 + vals0 ↔ vals = vals1], [CSIMPSEQ : ⊦ vals + val = vals + val '], [CSIMPSEQ : ⊦ ((* i)) + i0 - ((* j)) = (i - j) + i0], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0])]]