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Proof step 26 from proof get-rest (previous step)

(~1) ≤ i2, 0 < i2, ∀ i1, r, i, st. i→n(i1) < i→n(i2 + 1) → (0 ≤ i1 → getarray(r, i, i1 + 1, st) .rest = getarray(r, i + 1, i1, st)) ⊦ getarray(r, i, 2 + i2, st) .rest = getarray(r, i + 1, i2, st) + st[r -- (i + i2 + 1) '] '

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 15:
⊦ getarray(r, i, j, st) = [] ↔ j ≤ 0
Proof step 25:
getarray(r, i, 2 + i2, st) = val + vals ∧ getarray(r, i, 2 + i2, st) ≠ [], (~1) ≤ i2, 0 < i2, ∀ i1, r, i, st. i→n(i1) < i→n(i2 + 1) → (0 ≤ i1 → getarray(r, i, i1 + 1, st) .rest = getarray(r, i + 1, i1, st)) ⊦ vals = getarray(r, i + 1, i2, st) + st[r -- (i + i2 + 1) '] '

Rule argument

[speclemmaarg: vals ≠ [] ,val = vals .first ∧ vals0 = vals .rest ↔ vals = val + vals0 ,[vals, val, vals0] → [getarray(r, i, 2 + i2, st), val, vals] ,T ,list-data ,javavalues ,elim-list-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + ((* j)) ≤ ((* j0)) ↔ i ≤ j0 - j], [CSIMPSEQ : ⊦ i < 0 ∧ 0 < j → ¬ j ≤ i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPELIM : vals ≠ [] ⊦ val = vals .first ∧ vals0 = vals .rest ↔ vals = val + vals0])], [EXTRATERMS : (getarray(r, i, 2 + i2, st), val, vals)]]