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Proof step 16 from proof get-sublist (previous step)

n→i(n) ≤ j ⊦ sublist(0, n, getarray(r, i, j, st)) = getarray(r, i, n→i(n), st)

User applied rule structural induction

And obtained the following new goals

Proof step 1:
⊦ getarray(r, i, 0, st) = []
Proof step 15:
∀ j, r, i, st. n→i(m) ≤ j → sublist(0, m, getarray(r, i, j, st)) = getarray(r, i, n→i(m), st) ⊦ n→i(m +1) ≤ j → sublist(0, m +1, getarray(r, i, j, st)) = getarray(r, i, n→i(m +1), st)

Rule argument

[VARWITHFMAVARSARG : n, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : nat generated by 0, +1;], [CSIMPSEQ : ⊦ sublist(0, 0, vals) = []])]]