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Proof step 9 from proof get-sublist (previous step)

n→i(m) ≤ i1, 0 ≤ i1, ¬ i1 < n→i(m) → sublist(0, m, getarray(r, i + 1, i1, st)) = getarray(r, i + 1, n→i(m), st) ⊦ st[r -- i '] ' + sublist(0, m, getarray(r, i + 1, i1, st)) = getarray(r, i, n→i(m) + 1, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
sublist(0, m, getarray(r, i + 1, i1, st)) = getarray(r, i + 1, n→i(m), st), n→i(m) ≤ i1, 0 ≤ i1 ⊦ st[r -- i '] ' + getarray(r, i + 1, n→i(m), st) = getarray(r, i, n→i(m) + 1, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i ≤ j → (¬ ¬ j < i ↔ false)])]]