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Proof step 28 from proof getarray-in-01 (previous step)

0 < i1 ⊦ val ∈ getarray(r, i0, i1, st) ↔ (∃ i. ¬ i < i0 ∧ ¬ i0 + i1 ≤ i ∧ st[r -- i '] = val)

User applied rule case distinction

And obtained the following new goals

Proof step 17:
val ∈ getarray(r, i0, i1, st), 0 < i1 ⊦ ∃ i. ¬ i < i0 ∧ ¬ i0 + i1 ≤ i ∧ st[r -- i '] = val
Proof step 27:
∃ i. ¬ i < i0 ∧ ¬ i0 + i1 ≤ i ∧ st[r -- i '] = val, 0 < i1 ⊦ val ∈ getarray(r, i0, i1, st)

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]