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Proof step 10 from proof getarray-in (previous step)

n < i→n(st[r -- _length] .intval), 0 < st[r -- _length] .intval ⊦ getarray(r, st) = [], st[r -- _length] .intval = 0, ¬ n→i(n) < 0 ∧ ¬ st[r -- _length] .intval ≤ n→i(n) ∧ st[r -- n→i(n) '] = st[r -- n→i(n) ']

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
st[r -- _length] .intval ≤ n→i(n), 0 < st[r -- _length] .intval, n < i→n(st[r -- _length] .intval) ⊦ st[r -- _length] .intval = 0, getarray(r, st) = [], n = 0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ 0 < n ↔ n ≠ 0], [CSIMPSEQ : 0 ≤ i ⊦ ((* i)) < n→i(n) ↔ i→n(i) < n], [CSIMPFORWARD : ⊦ i ≤ j ∧ 0 < i → 0 < j], [CSIMPSEQ : ⊦ ¬ n→i(n) < 0])]]