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Proof step 11 from proof getarray-put-01 (previous step)

0 < j, i0 < i ∨ i + j ≤ i0, ∀ j0, i0, i, r, st, val. i→n(j0) < i→n(j) → (i0 < i ∨ i + j0 ≤ i0 → getarray(r, i, j0, st[r -- i0 ', val]) = getarray(r, i, j0, st)) ⊦ (st[r -- i0 ', val][r -- i ']) ' + getarray(r, i + 1, j - 1, st[r -- i0 ', val]) = getarray(r, i, j, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
0 < j, i0 < i ∨ i + j ≤ i0, ∀ j0, i0, i, r, st, val. i→n(j0) < i→n(j) → (i0 < i ∨ i + j0 ≤ i0 → getarray(r, i, j0, st[r -- i0 ', val]) = getarray(r, i, j0, st)) ⊦ ((i = i0 ⊃ val; st[r -- i '])) ' + getarray(r, i + 1, j - 1, st[r -- i0 ', val]) = getarray(r, i, j, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j], [CSIMPSEQ : ⊦ i ' = i0 ' ↔ i = i0], [CSIMPSEQ : ⊦ r -- sk = r0 -- sk0 ↔ ¬ ¬ (r = r0 ∧ sk = sk0)], [CSIMPSEQ : ⊦ (st[rk0, val][rk]) = ((rk = rk0 ⊃ val; st[rk]))])]]