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Proof step 15 from proof getarray-put-02 (previous step)

true, ∀ j0, r, r0, i, st, sk, val. i→n(j0) < i→n(j) → (true → r = r0 ∨ getarray(r, i, j0, st[r0 -- sk, val]) = getarray(r, i, j0, st)) ⊦ r = r0 ∨ getarray(r, i, j, st[r0 -- sk, val]) = getarray(r, i, j, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
∀ j0, r, r0, i, st, sk, val. i→n(j0) < i→n(j) → (true → r = r0 ∨ getarray(r, i, j0, st[r0 -- sk, val]) = getarray(r, i, j0, st)) ⊦ getarray(r, i, j, st[r0 -- sk, val]) = getarray(r, i, j, st), r = r0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]