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Proof step 5 from proof getarray-put-02 (previous step)

j ≤ 1, ∀ j0, r, r0, i, st, sk, val. i→n(j0) < i→n(j) → (true → r = r0 ∨ getarray(r, i, j0, st[r0 -- sk, val]) = getarray(r, i, j0, st)) ⊦ getarray(r, i, j, st[r0 -- sk, val]) = getarray(r, i, j, st), r = r0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ j ≤ 0 → getarray(r, i, j, st) = []
Proof step 3:
⊦ getarray(r, i, 1, st) = st[r -- i '] '
Proof step 4:
⊦ j ≤ 0 → getarray(r, i, j, st) = []

Rule argument

[crewrite-arg: getArray-zero , F , [st, j, i, r] → [st[r0 -- sk, val], j, i, r] ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i], [CSIMPSEQ : ⊦ 0 < i → (i ≤ 1 ↔ i = 1)], [CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j], [CSIMPSEQ : ⊦ r ≠ r0 → (st[r0 -- sk0, val][r -- sk]) = st[r -- sk]], [CSIMPSEQ : ⊦ val ' = val0 ' ↔ val = val0])], [EXTRATERMS : (st[r0 -- sk, val], j, i, r)]]