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Proof step 9 from proof getarray-put-03 (previous step)

1 < i0 + 1, 0 < i0, ∀ j0, r, i, st, r0, fs, val. i→n(j0) < i→n(i0 + 1) → (true → getarray(r, i, j0, st[r0 -- fs ', val]) = getarray(r, i, j0, st)) ⊦ getarray(r, i, i0, st[r0 -- fs ', val]) + st[r -- (i + i0) '] ' = getarray(r, i, i0 + 1 - 1, st) + st[r -- (i + i0 + 1 - 1) ']

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
0 < i0, ∀ j0, r, i, st, r0, fs, val. i→n(j0) < i→n(i0 + 1) → (true → getarray(r, i, j0, st[r0 -- fs ', val]) = getarray(r, i, j0, st)) ⊦ getarray(r, i, i0, st[r0 -- fs ', val]) = getarray(r, i, i0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ((* j)) < i0 + ((* j0)) ↔ j - j0 < i0], [CSIMPSEQ : ⊦ (vals + vals0) + vals1 = vals + vals0 + vals1], [CSIMPSEQ : ⊦ vals + vals0 = vals1 + vals0 ↔ vals = vals1], [CSIMPSEQ : ⊦ vals + val = vals + val '], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + 0 = i], [CSIMPSEQ : ⊦ ((* i)) + i0 - ((* j)) = (i - j) + i0], [CSIMPSEQ : ⊦ i + j = j + i])]]