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Proof step 24 from proof getarray-put=set (previous step)

i→n(i1) < # getarray(r, i, i0, st), 0 ≤ i0, 0 ≤ i1, i1 < i0, 0 < i0, ∀ val, st, i, r, i1, j0. i→n(j0) < i→n(i0 + 1) → (0 < j0 ∧ i1 < j0 ∧ 0 ≤ i1 → getarray(r, i, j0, st[r -- (i1 + i) ', val]) = (getarray(r, i, j0, st)[i→n(i1), val])) ⊦ i0 = i1, getarray(r, i, i0, st[r -- (i1 + i) ', val]) + st[r -- (i + i0) '] ' = (getarray(r, i, i0, st)[i→n(i1), val]) + st[r -- (i + i0) '] '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
⊦ 0 < j → # getarray(r, i, j, st) = i→n(j)
Proof step 23:
0 ≤ i0, 0 ≤ i1, 0 < i0, i1 < i0, ∀ val, st, i, r, i1, j0. i→n(j0) < i→n(i0 + 1) → (0 < j0 ∧ i1 < j0 ∧ 0 ≤ i1 → getarray(r, i, j0, st[r -- (i1 + i) ', val]) = (getarray(r, i, j0, st)[i→n(i1), val])) ⊦ i0 = i1, getarray(r, i, i0, st[r -- (i1 + i) ', val]) = (getarray(r, i, i0, st)[i→n(i1), val])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ 0 < j → abs(j) = j], [CSIMPSEQ : ⊦ 0 ≤ i → abs(i) = i], [CSIMPSEQ : ⊦ i→n(i) < i→n(j) ↔ abs(i) < abs(j)], [CSIMPSEQ : ⊦ (vals + vals0) + vals1 = vals + vals0 + vals1], [CSIMPSEQ : ⊦ vals + vals0 = vals1 + vals0 ↔ vals = vals1], [CSIMPSEQ : ⊦ i + j = j + i])]]