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Proof step 34 from proof getarray-put=set (previous step)

0 < j ∧ i1 < j ∧ 0 ≤ i1, ∀ val, st, i, r, i1, j0. i→n(j0) < i→n(j) → (0 < j0 ∧ i1 < j0 ∧ 0 ≤ i1 → getarray(r, i, j0, st[r -- (i1 + i) ', val]) = (getarray(r, i, j0, st)[i→n(i1), val])) ⊦ getarray(r, i, j, st[r -- (i1 + i) ', val]) = (getarray(r, i, j, st)[i→n(i1), val])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 33:
0 ≤ i1, i1 < j, 0 < j, ∀ val, st, i, r, i1, j0. i→n(j0) < i→n(j) → (0 < j0 ∧ i1 < j0 ∧ 0 ≤ i1 → getarray(r, i, j0, st[r -- (i1 + i) ', val]) = (getarray(r, i, j0, st)[i→n(i1), val])) ⊦ getarray(r, i, j, st[r -- (i1 + i) ', val]) = (getarray(r, i, j, st)[i→n(i1), val])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]