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Proof step 4 from proof getarray-putbar-01 (previous step)

∀ r, r1, i, j, i0, st. r = r1 ∨ getarray(r, i, j, putByteArray(bytes0, r1, i0, st)) = getarray(r, i, j, st) ⊦ r = r1, getarray(r, i, j, putByteArray(bytes0, r1, i0 + 1, st)) = getarray(r, i, j, st)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 1, [QUANTTERMLIST : (r, r1, i, j, i0 + 1, st)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, r1, i, j, i0 + 1, st)]]