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Proof step 8 from proof getarray-putbar (previous step)

∀ r, r1, i, j, st. r = r1 ∨ getarray(r, i, j, putByteArray(bytes0, r1, st)) = getarray(r, i, j, st) ⊦ r = r1, getarray(r, i, j, st) = getarray(r, i, j, putByteArray(bytes0, r1, 1, st))

User applied rule insert lemma

And obtained the following new goals

Proof step 7:
⊦ r ≠ r1 → getarray(r, i, j, putByteArray(bytes, r1, i0, st)) = getarray(r, i, j, st)

Rule argument

[LEMMAARG : getarray-putbar-01, [r, r1, i, j, bytes, i0, st] → [r, r1, i, j, bytes0, 1, st]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, r1, i, j, bytes0, 1, st)]]