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Proof step 5 from proof getba-eq (previous step)

st[r -- i1 '] = st[r1 -- i1 '], 0 < i0, i0 < i + i1, i1 < i0, 0 < i, 0 ≤ i1, 0 < i + i1, 1 < i + i1, ∀ i0. ¬ i0 < i1 ∧ ¬ i1 + i ≤ i0 → st[r -- i0 '] = st[r1 -- i0 '], ∀ r1, r, st, i1, i0. i→n(i0) < i→n(i) → ( 0 ≤ i0 ∧ 0 ≤ i1 ∧ (∀ i2. ¬ i2 < i1 ∧ ¬ i1 + i0 ≤ i2 → st[r -- i2 '] = st[r1 -- i2 ']) → getbytearray(r, i1, i0, st) = getbytearray(r1, i1, i0, st)) ⊦ st[r -- i0 '] = st[r1 -- i0 '], getbytearray(r, i1 + 1, i - 1, st) = getbytearray(r1, i1 + 1, i - 1, st), 0 = i

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 9, [QUANTTERMLIST : (i0)]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i < j → ¬ j < i], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i < j → (¬ ¬ j ≤ i ↔ false)])], [EXTRATERMS : (i0)]]