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Proof step 2 from proof getbar-appeq-01 (previous step)

0 ≤ j ⊦ getbytearray(r, i, j, st) + bytes = getbytearray(r0, i0, j, st) + bytes0 ↔ getbytearray(r, i, j, st) = getbytearray(r0, i0, j, st) ∧ bytes = bytes0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ 0 ≤ j → ( getbytearray(r, i, j, st) + bytes = getbytearray(r0, i0, j, st) + bytes0 ↔ getbytearray(r, i, j, st) = getbytearray(r0, i0, j, st) ∧ bytes = bytes0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1])]]