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Proof step 7 from proof getbar-putbar-same-01 (previous step)

∀ r, i, st. getbytearray(r, i, n→i(# bytes0), putByteArray(bytes0, r, i, st)) = bytes0 ⊦ getbytearray(r, i + 1, n→i(# bytes0), putByteArray(bytes0, r, i + 1, st)[r -- i ', byteval(by)]) = bytes0

User applied rule all left

And obtained the following new goals

Proof step 6:
getbytearray(r, i + 1, n→i(# bytes0), putByteArray(bytes0, r, i + 1, st)) = bytes0, ∀ r, i, st. getbytearray(r, i, n→i(# bytes0), putByteArray(bytes0, r, i, st)) = bytes0 ⊦ getbytearray(r, i + 1, n→i(# bytes0), putByteArray(bytes0, r, i + 1, st)[r -- i ', byteval(by)]) = bytes0

Rule argument

[EXRARG : pos: left 1, [extquanttermlist: (r, i + 1, st) abort:F , discard:F , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, i + 1, st)]]