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Proof step 9 from proof getbar-restn-01 (previous step)

n ≤ # getbytearray(r, 0, n→i(n), st), st[r -- _length] .intval = i + n→i(n), 0 ≤ i ⊦ restn(n, getbytearray(r, 0, n→i(n), st)) + getbytearray(r, n→i(n), i, st) = getbytearray(r, n→i(n), i, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ # getbytearray(r, i, n→i(m), st) = m
Proof step 8:
st[r -- _length] .intval = i + n→i(n), 0 ≤ i ⊦ restn(n, getbytearray(r, 0, n→i(n), st)) = []

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m ≤ m], [CSIMPSEQ : ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1], [CSIMPSEQ : ⊦ bytes = bytes0 + bytes ↔ bytes0 = []])]]