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Proof step 4 from proof getbar-union-02 (previous step)

st .refs ∩ st0 .refs = ∅, r ∈ st, r ∈ st0 .refs ⊦ st0 .refs = ∅, getbytearray(r, i, j, st ∪ st0) = getbytearray(r, i, j, st0), # st0 .refs = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[speclemmaarg: ,r ∈ st .refs ↔ r ∈ st ,[st, r] → [st, r] ,T ,storefunsx , ,refs-def ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (rset ∩ rset0) ∩ rset1 = rset ∩ rset0 ∩ rset1], [CSIMPSEQ : ⊦ rset ∩ rset0 = rset0 ∩ rset], [CSIMPSEQ : ⊦ rset ∩ rset0 = ∅ ∧ r ∈ rset → (¬ ¬ r ∈ rset0 ↔ false)])], [EXTRATERMS : (st, r)]]