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Proof step 12 from proof getbar-union (conclusion)

⊦ st .refs ∩ st0 .refs = ∅ ∧ r ∈ st0 → getbytearray(r, st ∪ st0) = getbytearray(r, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
st .refs ∩ st0 .refs = ∅, r ∈ st0 ⊦ getbytearray(r, st ∪ st0) = getbytearray(r, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]