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Proof step 6 from proof getbar-union (previous step)

¬ r ∈ st ∨ ¬ r ∈ st0 .refs, ∀ r. ¬ r ∈ st .refs ∨ ¬ r ∈ st0 .refs, r ∈ st0, r ∈ st ⊦ getbytearray(r, st ∪ st0) = getbytearray(r, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
r ∈ st0, r ∈ st, ∀ r. ¬ r ∈ st .refs ∨ ¬ r ∈ st0 .refs ⊦ getbytearray(r, st ∪ st0) = getbytearray(r, st0), r ∈ st0 .refs

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]