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Proof step 14 from proof getbytearray-subset (previous step)

n→i(n) < j, n→i(n) < j, n < i→n(j), 0 ≤ i, st ⊆ st0, 0 < j, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ st[r -- (i + n→i(n)) '] .byteval = st0[r -- (i + n→i(n)) '] .byteval, j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ rk ∈ st ∧ st ⊆ st1 → st[rk] = st1[rk]
Proof step 13:
¬ (r -- (i + n→i(n)) ' ∈ st ∧ st ⊆ st0), n→i(n) < j, n→i(n) < j, n < i→n(j), 0 ≤ i, st ⊆ st0, 0 < j, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ st[r -- (i + n→i(n)) '] .byteval = st0[r -- (i + n→i(n)) '] .byteval, j = 0

Rule argument

[speclemmaarg: ,rk ∈ st ∧ st ⊆ st1 → st[rk] = st1[rk] ,[rk, st, st1] → [r -- (i + n→i(n)) ', st, st0] ,F ,store ,javastore-ostorea ,subset-elem-eq ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r -- (i + n→i(n)) ', st, st0)]]