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Proof step 16 from proof getbytearray-subset (previous step)

n < i→n(j), 0 ≤ i, st ⊆ st0, 0 < j, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ (getbytearray(r, i, j, st)[n]) = (getbytearray(r, i, j, st0)[n]), j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ n→i(n) < j → (getbytearray(r, i, j, st)[n]) = st[r -- (i + n→i(n)) '] .byteval
Proof step 9:
¬ n→i(n) < j, n < i→n(j), 0 ≤ i, st ⊆ st0, 0 < j, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ (getbytearray(r, i, j, st)[n]) = (getbytearray(r, i, j, st0)[n]), j = 0
Proof step 15:
n→i(n) < j, n < i→n(j), 0 ≤ i, st ⊆ st0, 0 < j, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ st[r -- (i + n→i(n)) '] .byteval = (getbytearray(r, i, j, st0)[n]), j = 0

Rule argument

[crewrite-arg: bar-at, F, [n, st, j, i, r] → [n, st, j, i, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (n, st, j, i, r)]]