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Proof step 19 from proof getbytearray-subset (previous step)

st ⊆ st0, 0 ≤ i, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ # getbytearray(r, i, j, st) = # getbytearray(r, i, j, st0) ∧ (∀ n. n < # getbytearray(r, i, j, st) → (getbytearray(r, i, j, st)[n]) = (getbytearray(r, i, j, st0)[n]))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
st ⊆ st0, 0 ≤ i, ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ # getbytearray(r, i, j, st) = # getbytearray(r, i, j, st0) ∧ (n < # getbytearray(r, i, j, st) → (getbytearray(r, i, j, st)[n]) = (getbytearray(r, i, j, st0)[n]))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]