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Proof step 8 from proof getbytearray-subset (previous step)

j ≤ n→i(n), 0 < j, st ⊆ st0, 0 ≤ i, n < i→n(j), ∀ j0. ¬ j0 < 0 ∧ ¬ i + j ≤ j0 → r -- j0 ' ∈ st ⊦ j = 0, (getbytearray(r, i, j, st)[n]) = (getbytearray(r, i, j, st0)[n]), n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
0 ≤ i ⊦ ((* m)) < i→n(i) ↔ n→i(m) < i

Rule argument

[speclemmaarg: 0 ≤ i ,((* m)) < i→n(i) ↔ n→i(m) < i ,[i, m] → [j, n] ,F ,intnat , ,num-i2n-ls-02 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i < j → ¬ j < i], [CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i], [CSIMPSEQ : ⊦ i ≠ j → (i ≤ j ↔ i < j)], [CSIMPSEQ : ⊦ i < j → (¬ ¬ j ≤ i ↔ false)])], [EXTRATERMS : (j, n)]]