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Proof step 10 from proof getintarray-at (previous step)

j ≤ n→i(n), n < i→n(j), 0 < j ⊦ j = 0, (getarray(r, i, j, st)[n]) .intval = st[r -- (i + n→i(n)) '] .intval, n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
0 ≤ i ⊦ ((* m)) < i→n(i) ↔ n→i(m) < i
Proof step 9:
⊦ n→i(n) < j → (getarray(r, i, j, st)[n]) = st[r -- (i + n→i(n)) ']

Rule argument

[speclemmaarg: 0 ≤ i ,((* m)) < i→n(i) ↔ n→i(m) < i ,[i, m] → [j, n] ,F ,intnat , ,num-i2n-ls-02 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i], [CSIMPSEQ : ⊦ i < j → ¬ j < i])], [EXTRATERMS : (j, n)]]