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Proof step 15 from proof getintarray-at (previous step)

n < # intvalues(getarray(r, i, j, st)), 0 < j ⊦ (intvalues(getarray(r, i, j, st))[n]) = st[r -- (i + n→i(n)) '] .intval

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ 0 < j → # getarray(r, i, j, st) = i→n(j)
Proof step 14:
n < i→n(j), 0 < j ⊦ (intvalues(getarray(r, i, j, st))[n]) = st[r -- (i + n→i(n)) '] .intval, j = 0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i→n(i) = 0 ↔ i = 0], [CSIMPFORWARD : ⊦ m < n → n ≠ 0], [CSIMPSEQ : ⊦ # intvalues(vals) = # vals])]]