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Proof step 17 from proof getintarray-at (conclusion)

⊦ n < # getintarray(r, i, j, st) → (getintarray(r, i, j, st)[n]) = st[r -- (i + n→i(n)) '] .intval

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ getintarray(r, i, j, st) = [] ↔ j ≤ 0
Proof step 16:
n < # getintarray(r, i, j, st), 0 < j ⊦ (getintarray(r, i, j, st)[n]) = st[r -- (i + n→i(n)) '] .intval

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j], [CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i], [CSIMPSEQ : ⊦ # ints = 0 ↔ ints = []], [CSIMPFORWARD : ⊦ m < n → n ≠ 0])]]