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Proof step 5 from proof getintarray-in-02 (previous step)

¬ 0 < j, ∀ st, i0, r, i, j0. i→n(j0) < i→n(j) → (true → (i ∈ getintarray(r, i0, j0, st) ↔ (∃ j1. i = st[r -- (i0 + j1) '] .intval ∧ ¬ j1 < 0 ∧ ¬ j0 ≤ j1))) ⊦ i ∈ getintarray(r, i0, j, st) ↔ (∃ j0. i = st[r -- (i0 + j0) '] .intval ∧ ¬ j0 < 0 ∧ ¬ j ≤ j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
j ≤ 0, ∀ st, i0, r, i, j0. i→n(j0) < i→n(j) → (true → (i ∈ getintarray(r, i0, j0, st) ↔ (∃ j1. i = st[r -- (i0 + j1) '] .intval ∧ ¬ j1 < 0 ∧ ¬ j0 ≤ j1))) ⊦ i ∈ getintarray(r, i0, j, st) ↔ (∃ j0. i = st[r -- (i0 + j0) '] .intval ∧ ¬ j0 < 0 ∧ ¬ j ≤ j0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0], [CSIMPSEQ : ⊦ ¬ i < j ↔ j ≤ i])]]