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Proof step 8 from proof getintarray-in-02 (previous step)

st[r -- (i0 + j) '] .intval ∈ getintarray(r, i0, i1, st), j < i1, 0 ≤ i1, 0 ≤ j, 0 < i1, ∀ st, i0, r, i, j0. i→n(j0) < i→n(i1 + 1) → (true → (i ∈ getintarray(r, i0, j0, st) ↔ (∃ j1. i = st[r -- (i0 + j1) '] .intval ∧ ¬ j1 < 0 ∧ ¬ j0 ≤ j1))) ⊦ ∃ j0. st[r -- (i0 + j) '] .intval = st[r -- (i0 + j0) '] .intval ∧ ¬ j0 < 0 ∧ ¬ i1 < j0

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

[EXRARG : pos: right 1, [QUANTTERMLIST : (j)]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i ≤ j → (¬ ¬ j < i ↔ false)], [CSIMPSEQ : ⊦ i < j → ¬ j < i])], [EXTRATERMS : (j)]]