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Proof step 10 from proof is_arrayref-01 (conclusion)

⊦ is_arrayref(r, i, st[_out, val]) ↔ is_arrayref(r, i, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ is_arrayref(r, i, st) ↔ (∀ j. 0 ≤ j ∧ j < i → r -- j ' ∈ st)
Proof step 9:
⊦ is_arrayref(r, i, st[_out, val]) ↔ (∀ j. 0 ≤ j ∧ j < i → r -- j ' ∈ st)

Rule argument

[crewrite-arg: is_arrayref, F, [st, i, r] → [st, i, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, i, r)]]