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Proof step 4 from proof is_arrayref-03 (previous step)

j0 < i, ∀ j. 0 ≤ j ∧ j < i → r -- j ' ∈ st, 0 ≤ j0, 0 < i ⊦ j0 = j, r -- j0 ' ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
j0 < i, 0 ≤ j0, 0 < i, ∀ j1. ¬ j1 < 0 ∧ ¬ i ≤ j1 → r -- j1 ' ∈ st ⊦ j0 = j, r -- j0 ' ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ i < j ↔ j ≤ i], [CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i])]]