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Proof step 6 from proof isarrayref-mod (previous step)

(∀ rk. rk ∈ st ↔ rk ∈ st0) ∧ (∀ r1, sk. r1 ≠ r0 → st[r1 -- sk] = st0[r1 -- sk]) ∧ (r0 -- _type ∈ st → st[r0 -- _type] = st0[r0 -- _type]) ∧ (r0 -- _length ∈ st → st[r0 -- _length] = st0[r0 -- _length]), j < i, 0 ≤ j, 0 < i, ∀ j. ¬ j < 0 ∧ ¬ i ≤ j → r -- j ' ∈ st ⊦ r = r0, r -- j ' ∈ st0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 < i, 0 ≤ j, j < i, ∀ j. ¬ j < 0 ∧ ¬ i ≤ j → r -- j ' ∈ st, r0 -- _length ∈ st → st[r0 -- _length] = st0[r0 -- _length], r0 -- _type ∈ st → st[r0 -- _type] = st0[r0 -- _type], ∀ r1, sk. r1 ≠ r0 → st[r1 -- sk] = st0[r1 -- sk], ∀ rk. rk ∈ st ↔ rk ∈ st0 ⊦ r = r0, r -- j ' ∈ st0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]