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Proof step 5 from proof putArray-append (conclusion)

⊦ putArray(vals + vals0, r, i, st) = putArray(vals, r, i, putArray(vals0, r, i + n→i(# vals), st))

User applied rule structural induction

And obtained the following new goals

Proof step 1:
⊦ putArray([], r, i, st) = st
Proof step 4:
∀ vals0, r, i, st. putArray(vals1 + vals0, r, i, st) = putArray(vals1, r, i, putArray(vals0, r, i + n→i(# vals1), st)) ⊦ putArray((val + vals1) + vals0, r, i, st) = putArray(val + vals1, r, i, putArray(vals0, r, i + n→i(# (val + vals1)), st))

Rule argument

[VARWITHVARSEQSARG : vals, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : javavalues generated by [], +;], [CSIMPSEQ : ⊦ [] + vals = vals], [CSIMPSEQ : ⊦ (vals + vals0) + vals1 = vals + vals0 + vals1], [CSIMPSEQ : ⊦ # [] = 0], [CSIMPSEQ : ⊦ i + 0 = i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + j = j + i])]]