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Proof step 3 from proof putArray-at (previous step)

is_fskey(sk) ⊦ (putArray(vals, r, i, st)[r -- sk]) = st[r -- sk]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ is_fskey(sk) ↔ (∃ fs. sk = fs ')
Proof step 2:
⊦ (putArray(vals, r, j, st)[r0 -- fs ']) = st[r0 -- fs ']

Rule argument

[speclemmaarg: ,is_fskey(sk) ↔ (∃ fs. sk = fs ') ,[sk] → [sk] ,F ,storekey , ,ex-03 ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk)]]