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Proof step 6 from proof putArray-put-switch (previous step)

0 ≤ j, 0 ≤ i, n→i(# vals0) + i < j, ∀ i0, j0, r0, st0, val1. ¬ j0 < i0 + n→i(# vals0) ∧ ¬ j0 < 0 ∧ ¬ i0 < 0 → putArray(vals0, r0, i0, st0[r0 -- j0 ', val1]) = (putArray(vals0, r0, i0, st0)[r0 -- j0 ', val1]) ⊦ (putArray(vals0, r, i + 1, st[r -- j ', val])[r -- i ', val0]) = (putArray(vals0, r, i + 1, st)[r -- i ', val0][r -- j ', val])

User applied rule all left

And obtained the following new goals

Proof step 5:
0 ≤ j, 0 ≤ i, n→i(# vals0) + i < j, ¬ j < (i + 1) + n→i(# vals0) ∧ ¬ j < 0 ∧ ¬ i + 1 < 0 → putArray(vals0, r, i + 1, st[r -- j ', val]) = (putArray(vals0, r, i + 1, st)[r -- j ', val]), ∀ i0, j0, r0, st0, val1. ¬ j0 < i0 + n→i(# vals0) ∧ ¬ j0 < 0 ∧ ¬ i0 < 0 → putArray(vals0, r0, i0, st0[r0 -- j0 ', val1]) = (putArray(vals0, r0, i0, st0)[r0 -- j0 ', val1]) ⊦ (putArray(vals0, r, i + 1, st[r -- j ', val])[r -- i ', val0]) = (putArray(vals0, r, i + 1, st)[r -- i ', val0][r -- j ', val])

Rule argument

[EXRARG : pos: left 4, [extquanttermlist: (i + 1, j, r, st, val) abort:F , discard:F , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (i + 1, j, r, st, val)]]