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Proof step 22 from proof putar-getar (previous step)

n→i(# vals0) = i1 + 1, ∀ r0, i0, st0. getarray(r0, i0, n→i(# vals0), putArray(vals0, r0, i0, st0)) = vals0 ⊦ vals0 = [], getarray(r, i, n→i(# vals0), putArray(vals0, r, i + 1, st)[r -- i ', val]) + vals0[i→n(i1)] ' = val ' + vals0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
n→i(# vals0) = i1 + 1, ∀ r0, i0, st0. getarray(r0, i0, i1 + 1, putArray(vals0, r0, i0, st0)) = vals0 ⊦ vals0 = [], getarray(r, i, i1 + 1, putArray(vals0, r, i + 1, st)[r -- i ', val]) + vals0[i→n(i1)] ' = val ' + vals0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]