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Proof step 4 from proof putarray-subset-new (previous step)

⊦ st ⊆ putArray(vals, r, st0) ↔ st ⊆ st0, r ∈ st

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[crewrite-arg: putArray-all, F, [st, r, vals] → [st0, r, vals]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st0, r, vals)]]