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Proof step 11 from proof putbar-byte (previous step)

j = i0 + i, j < i + n→i(# bytes), i ≤ j ⊦ (putByteArray(bytes, r, i, st)[r -- j ']) = byteval(bytes[i→n(i0)]), bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
0 ≤ i0, i0 < n→i(# bytes) ⊦ bytes = [], (putByteArray(bytes, r, i, st)[r -- (i0 + i) ']) = byteval(bytes[i→n(i0)])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ # bytes = 0 ↔ bytes = []], [CSIMPSEQ : ⊦ 0 < n ↔ n ≠ 0], [CSIMPSEQ : 0 ≤ i ⊦ ((* i)) < n→i(n) ↔ i→n(i) < n], [CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPFORWARD : ⊦ i ≤ j ∧ j < j0 → i < j0], [CSIMPSEQ : ⊦ i ≤ i + j ↔ 0 ≤ j], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + j < i + i0 ↔ j < i0])]]