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Proof step 6 from proof putbar-byte (previous step)

¬ (0 ≤ i→n(i0) ∧ i→n(i0) < # bytes), 0 ≤ i0, i0 < n→i(# bytes) ⊦ bytes = [], (mkjavavalues(bytes)[i→n(i0)]) = byteval(bytes[i→n(i0)])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 ≤ i0, i0 < n→i(# bytes), # bytes ≤ i→n(i0) ⊦ bytes = [], (mkjavavalues(bytes)[i→n(i0)]) = byteval(bytes[i→n(i0)])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ m < n ↔ n ≤ m], [CSIMPSEQ : ⊦ 0 ≤ m])]]