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Proof step 8 from proof putbar-byte (previous step)

i ≤ i0 + i ∧ i0 + i < n→i(# mkjavavalues(bytes)) + i, 0 ≤ i0, i0 < n→i(# bytes) ⊦ bytes = [], (mkjavavalues(bytes)[i→n(i0 + i - i)]) = byteval(bytes[i→n(i0)])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
0 ≤ i0, i0 < n→i(# bytes) ⊦ bytes = [], (mkjavavalues(bytes)[i→n(i0)]) = byteval(bytes[i→n(i0)])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + j < i + i0 ↔ j < i0], [CSIMPSEQ : ⊦ # mkjavavalues(bytes) = # bytes], [CSIMPSEQ : ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j], [CSIMPSEQ : ⊦ i ≤ i + j ↔ 0 ≤ j], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + j - i = j])]]