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Proof step 11 from proof putbar-getbar-le (previous step)

j = i1 + 1, i→n(j) = m + 1, 0 < j, j ≤ 1 + n→i(# bytes0), ∀ j0, r0, i0, st0. ¬ j0 < 0 ∧ ¬ n→i(# bytes0) < j0 → getbytearray(r0, i0, j0, putByteArray(bytes0, r0, i0, st0)) = firstn(i→n(j0), bytes0) ⊦ j = 0, getbytearray(r, i + 1, i1, putByteArray(bytes0, r, i + 1, st)[r -- i ', byteval(by)]) = firstn(m, bytes0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
0 ≤ i1, i1 ≤ n→i(# bytes0), ∀ j0, r0, i0, st0. ¬ j0 < 0 ∧ ¬ n→i(# bytes0) < j0 → getbytearray(r0, i0, j0, putByteArray(bytes0, r0, i0, st0)) = firstn(i→n(j0), bytes0) ⊦ (~1) = i1, getbytearray(r, i + 1, i1, putByteArray(bytes0, r, i + 1, st)[r -- i ', byteval(by)]) = firstn(i→n(i1), bytes0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ 0 ≤ n→i(n)], [CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPSEQ : ⊦ i + j ≤ i0 + j ↔ i ≤ i0], [CSIMPSEQ : ⊦ (~1) < i ↔ 0 ≤ i], [CSIMPSEQ : ⊦ ((* j)) < i0 + ((* j0)) ↔ j - j0 < i0], [CSIMPSEQ : ⊦ ((* j)) = i0 + ((* j0)) ↔ j - j0 = i0], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + n = m + n0 ↔ n = n0], [CSIMPSEQ : ⊦ 0 < i + 1 → i→n(i + 1) = i→n(i) + 1], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0])]]