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Proof step 23 from proof putbar-getbar-le (conclusion)

⊦ j ≤ n→i(# bytes) ∧ 0 ≤ j → getbytearray(r, i, j, putByteArray(bytes, r, i, st)) = firstn(i→n(j), bytes)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
0 ≤ j, j ≤ n→i(# bytes) ⊦ getbytearray(r, i, j, putByteArray(bytes, r, i, st)) = firstn(i→n(j), bytes)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ 0 ≤ n→i(n)], [CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPFORWARD : ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1])]]