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Proof step 5 from proof putbar-inother (conclusion)

⊦ i < j ∨ n→i(# bytes) + j ≤ i → (r0 -- i ' ∈ putByteArray(bytes, r, j, st) ↔ r0 -- i ' ∈ st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
i < j ∨ n→i(# bytes) + j ≤ i ⊦ r0 -- i ' ∈ putByteArray(bytes, r, j, st) ↔ r0 -- i ' ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]