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Proof step 3 from proof putbytearray-subset-new (previous step)

⊦ st ⊆ putByteArray(bytes, r, 0, st0) ↔ st ⊆ st0, r ∈ st

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ ¬ r ∈ st → (st ⊆ putByteArray(bytes, r, i, st0) ↔ st ⊆ st0)

Rule argument

[crewrite-arg: putbytearray-subset-new-01 , F , [st0, i, r, bytes, st] → [st0, 0, r, bytes, st] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st0, 0, r, bytes, st)]]