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Proof step 4 from proof sublist-getbar (conclusion)

⊦ n→i(n) + n→i(n0) ≤ st[r -- _length] .intval → sublist(n, n0, getbytearray(r, st)) = getbytearray(r, n→i(n), n→i(n0), st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ getbytearray(r, st) = getbytearray(r, 0, st[r -- _length] .intval, st)
Proof step 3:
⊦ n→i(n) + n→i(n0) ≤ st[r -- _length] .intval → sublist(n, n0, getbytearray(r, 0, st[r -- _length] .intval, st)) = getbytearray(r, n→i(n), n→i(n0), st)

Rule argument

[crewrite-arg: getByteArray-all, F, [st, r] → [st, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r)]]