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Proof step 4 from proof at-put-first-03 (previous step)

str ≠ str0 ⊦ (st[r -- mkfs(class, ty, str .field) ', val][r -- (mkfs(class, ty, str .field) ' ' + mkfs(class0, ty0, str0 .field) ' ')]) = st[val .refval -- mkfs(class0, ty0, str0 .field) ']

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ str = str0, (st[r -- mkfs(class, ty, str .field) ', val][r -- (mkfs(class, ty, str .field) ' ' + mkfs(class0, ty0, str0 .field) ' ')]) = st[val .refval -- mkfs(class0, ty0, str0 .field) ']

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]