[Imprint]
[Data Privacy Statement]
[E-Mail]
View
long theorem info
. View
the proof
. Back to
main index
. View
the specification
. View
theorem base summary
, View
theorem base listing
, the
used properties by spec
, the
dependency list
, the
symbol table
,
Proof step 2 from proof at-put-first-05 (
previous step
)
⊦ sks0 ≠ [] → (st[r -- (sk ' + sk0 '), val][st[r -- sk] .refval -- (sk0 ' + sks0)]) = (st[r -- (sk ' + sk0 '), val][val .refval -- sks0])
Lemma
at-put-first-04